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7x^2=243
We move all terms to the left:
7x^2-(243)=0
a = 7; b = 0; c = -243;
Δ = b2-4ac
Δ = 02-4·7·(-243)
Δ = 6804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6804}=\sqrt{324*21}=\sqrt{324}*\sqrt{21}=18\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{21}}{2*7}=\frac{0-18\sqrt{21}}{14} =-\frac{18\sqrt{21}}{14} =-\frac{9\sqrt{21}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{21}}{2*7}=\frac{0+18\sqrt{21}}{14} =\frac{18\sqrt{21}}{14} =\frac{9\sqrt{21}}{7} $
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